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/*
* [The "BSD licence"]
* Copyright (c) 2005-2008 Terence Parr
* All rights reserved.
*
* Conversion to C#:
* Copyright (c) 2008-2009 Sam Harwell, Pixel Mine, Inc.
* All rights reserved.
*
* Redistribution and use in source and binary forms, with or without
* modification, are permitted provided that the following conditions
* are met:
* 1. Redistributions of source code must retain the above copyright
* notice, this list of conditions and the following disclaimer.
* 2. Redistributions in binary form must reproduce the above copyright
* notice, this list of conditions and the following disclaimer in the
* documentation and/or other materials provided with the distribution.
* 3. The name of the author may not be used to endorse or promote products
* derived from this software without specific prior written permission.
*
* THIS SOFTWARE IS PROVIDED BY THE AUTHOR ``AS IS'' AND ANY EXPRESS OR
* IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES
* OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE DISCLAIMED.
* IN NO EVENT SHALL THE AUTHOR BE LIABLE FOR ANY DIRECT, INDIRECT,
* INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT
* NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE,
* DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY
* THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
* (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF
* THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
*/
namespace Antlr.Runtime.Tree
{
public interface ITreeNodeStream<T>
{
/** <summary>
* Get a tree node at an absolute index i; 0..n-1.
* If you don't want to buffer up nodes, then this method makes no
* sense for you.
* </summary>
*/
T this[int i]
{
get;
}
/** <summary>
* Get tree node at current input pointer + i ahead where i=1 is next node.
* i<0 indicates nodes in the past. So LT(-1) is previous node, but
* implementations are not required to provide results for k < -1.
* LT(0) is undefined. For i>=n, return null.
* Return null for LT(0) and any index that results in an absolute address
* that is negative.
* </summary>
*
* <remarks>
* This is analogus to the LT() method of the TokenStream, but this
* returns a tree node instead of a token. Makes code gen identical
* for both parser and tree grammars. :)
* </remarks>
*/
T LT(int k);
/** <summary>
* Where is this stream pulling nodes from? This is not the name, but
* the object that provides node objects.
* </summary>
*/
object TreeSource
{
get;
}
/** <summary>
* If the tree associated with this stream was created from a TokenStream,
* you can specify it here. Used to do rule $text attribute in tree
* parser. Optional unless you use tree parser rule text attribute
* or output=template and rewrite=true options.
* </summary>
*/
ITokenStream TokenStream
{
get;
}
/** <summary>
* What adaptor can tell me how to interpret/navigate nodes and
* trees. E.g., get text of a node.
* </summary>
*/
ITreeAdaptor<T> TreeAdaptor
{
get;
}
/** <summary>
* As we flatten the tree, we use UP, DOWN nodes to represent
* the tree structure. When debugging we need unique nodes
* so we have to instantiate new ones. When doing normal tree
* parsing, it's slow and a waste of memory to create unique
* navigation nodes. Default should be false;
* </summary>
*/
bool UniqueNavigationNodes
{
get;
set;
}
/** <summary>
* Return the text of all nodes from start to stop, inclusive.
* If the stream does not buffer all the nodes then it can still
* walk recursively from start until stop. You can always return
* null or "" too, but users should not access $ruleLabel.text in
* an action of course in that case.
* </summary>
*/
string ToString(T start, T stop);
#region REWRITING TREES (used by tree parser)
/** <summary>
* Replace from start to stop child index of parent with t, which might
* be a list. Number of children may be different
* after this call. The stream is notified because it is walking the
* tree and might need to know you are monkeying with the underlying
* tree. Also, it might be able to modify the node stream to avoid
* restreaming for future phases.
* </summary>
*
* <remarks>
* If parent is null, don't do anything; must be at root of overall tree.
* Can't replace whatever points to the parent externally. Do nothing.
* </remarks>
*/
void ReplaceChildren(T parent, int startChildIndex, int stopChildIndex, T t);
#endregion
}
}
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